python - What is the most pythonic way to iterate over OrderedDict -

i have ordereddict , in loop want index, key , value. it's sure can done in multiple ways, i.e.

a = collections.ordereddict({…}) i,b,c in zip(range(len(a)), a.iterkeys(), a.itervalues()):   … 

but avoid range(len(a)) , shorten a.iterkeys(), a.itervalues() a.iteritems(). enumerate , iteritems it's possible rephrase as

for i,d in enumerate(a.iteritems()):   b,c = d 

but requires unpack inside loop body. there way unpack in statement or maybe more elegant way iterate?

you can use tuple unpacking in for statement:

for i, (key, value) in enumerate(a.iteritems()):     # i, key, value 

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>>> d = {'a': 'b'} >>> i, (key, value) in enumerate(d.iteritems()): ...     print i, key, value ...  0 b 

side note:

in python 3.x, use dict.items() returns iterable dictionary view.

>>> i, (key, value) in enumerate(d.items()): ...     print(i, key, value)