php - get background image of tag using dom -

using dom, want show image in new html page <a> tag via id mentioned..

 <a class="lazy clogo" id="newphoto0" href="javascript:;" title="abc" onclick="opengall('phouter', '0612px612.x612.100906141758.c1u8', 'newphoto0');" data-original="http://content4.jdmagicbox.com/patna/u8/0612px612.x612.100906141758.c1u8/catalogue/10729ad97cafdc32d7957a5729aefb17.jpg" style="background: url(http://content4.jdmagicbox.com/patna/u8/0612px612.x612.100906141758.c1u8/catalogue/10729ad97cafdc32d7957a5729aefb17.jpg) 50% 50% / cover no-repeat;"><span class="rghtimgarw"></span></a>      <a class="lazy clogo" id="newphoto1" href="javascript:;" title="xyz" onclick="opengall('phouter', '0612px612.x612.130831165451.v7j7', 'newphoto2');" data-original="http://content2.jdmagicbox.com/patna/j7/0612px612.x612.130831165451.v7j7/catalogue/c2e023156401eedfa089b18d9595f623.gif" style="background: url(http://content2.jdmagicbox.com/patna/j7/0612px612.x612.130831165451.v7j7/catalogue/c2e023156401eedfa089b18d9595f623.gif) 50% 50% / cover no-repeat;"><span class="rghtimgarw"></span></a> 

i tried :

    $picks=$dom-> getelementbyid("newphoto".$i)->getattribute('style');     $photo=$picks->nodevalue;     echo $photo; 

but not working because image url mentioned in inline css..!

in more details : have html page want capture image using tag id. i'm not sure how capture image url , echo image using getvaluebyid?

you can use .css() background image value along .replace() filter out other part:

$('#newphoto0').css('background-image').replace('url(','').replace(')',''); 

and

$('#newphoto1').css('background-image').replace('url(','').replace(')',''); 

update: urls in array

$(".lazy.clogo").map(function(){   return $(this).css('background-image').replace('url(','').replace(')',''); }).get();