c++ - Convert MSB first to LSB first -

i want convert unsigned short value msb first lsb first. did below code not working. can point error did

#include <iostream> using namespace std; int main() {   unsigned short value = 0x000a;   char *m_pcurrent = (char *)&value;   short temp;   temp = *(m_pcurrent+1);          temp = (temp << 8) | *(unsigned char *)m_pcurrent;   m_pcurrent += sizeof(short);    cout << "temp    " << temp << endl;    return 0; } 

what wrong first assigned value's msb temp's lsb, shifted again msb , assigned value's lsb lsb. basically, had interchanged *(m_pcurrent + 1) , *m_pcurrent whole thing had no effect.

the simplified code:

#include <iostream> using namespace std;  int main() {     unsigned short value = 0x00ff;     short temp = ((char*) &value)[0];           // assign value's lsb     temp = (temp << 8) | ((char*) &value)[1];   // shift lsb msb , add value's msb     cout << "temp    " << temp << endl;     return 0; }